本文主要向大家介绍了 C/C++知识点之c/c++ 标准顺序容器 容器的访问，删除 操作，通过具体的内容向大家展示，希望对大家学习C/C++知识点有所帮助。

pop_front：vector，string不支持
pop_back:forward_list不支持
知识点
1，front, back, at 成员函数的使用，对应代码里的test1
2，删除最后一个元素pop_back, 删除第一个元素pop_front，对应代码里的test2
3，删除指定位置的元素erase，并返回下一位置的迭代器 ，对应代码里的test3
#include 
#include 
#include 
#include 
#include 

using namespace std;

int main(){
  //test1 顺序容器的front, back(forward_list没有back),at成员函数                
  //front返回容器里的头元素；back返回容器里的最后一个元素                       
  /*                                                                            
  //在解引用一个迭代器或调用front，back之前要检查容器里是否有元素               
  deque li{1,2,3,4};                                                       
  if(!li.empty()){                                                              
    auto val = *li.begin();                                                     
    val = 9;//不会改变容器里头元素的值                                          
    cout << li.front() << endl;                                                 
    auto val2 = li.front();                                                     
    val2 = 8;//不会改变容器里头元素的值                                         
    cout << li.front() << endl;                                                 
    auto& val3 = *li.begin();                                                   
    val3 = 9;//会改变容器里头元素的值                                           
    cout << li.front() << endl;                                                 
    auto& val4 = li.front();                                                    
    val4 = 8;//会改变容器里头元素的值                                           
    cout << li.front() << endl;                                                 
                                                                                
    auto val5 = li.end();                                                        
    //得到容器的最后一个元素                                                    
    auto last = *(--val5);                                                      
    cout << last << endl;                                                       
                                                                                
    auto v = li.at(1);                                                          
    auto v1 = li[2];                                                            
    cout << v << " " << v1 << endl;                                             
  }                                                                             
  */

  //test2 pop_back, pop_front                                                   
  //pop_back:删除容器的最后一个元素；pop_front:删除容器的第一个元素             
  /*                                                                            
  list li{1,2,3,4};                                                        
  if(!li.empty()){                                                              
    li.pop_back();                                                              
    cout << li.back() << endl;                                                  
    li.pop_front();                                                             
    cout << li.front() << endl;                                                 
  }                                                                             
  */

  //test3 erase                                                                 
  //删除指定位置的元素，并放回指向删除元素的下一个元素的迭代器                  
  vector li{0,1,2,3,4,5,6,7,8};
  //删除奇数                                                                    
  auto b = li.begin();
  while(b != li.end()){
    if(*b % 2){
      b = li.erase(b);
    }
    else{
      ++b;
    }
  }
  for(auto const &s : li){
    cout << s << " ";
  }
  cout << endl;

  auto it = li.begin();
  li.erase(it, it + 2);
  for(auto const &s : li){
    cout << s << " ";
  }
  cout << endl;

}

本文由职坐标整理并发布，希望对同学们有所帮助。了解更多详情请关注职坐标编程语言C/C+频道！